Arranging given Word in Alphabetical Order in JAVA

Arrange the String in Alphabetical Order

In this program we will input a word from user and arrange it in alphabetical order.

Example : Input : Computer

                Output : Cemoprtu

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Algorithm and Program given below :-

Algorithm :-

• Input a word

• Find its length

• Start a for loop in alphabetical order of Ascii Code

• Inside the Ascii code loop, start another loop and extract character from the string

• If the character is same as the given ascii code

• Store it in another variable

• close both the loops

• Print this variable, This will display string in Alphabetical order.

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Program :-

import java.io.*; import java.util.*; class Alphabetical {     public static void main(String args[])     {         Scanner in = new Scanner(System.in);         String str,str1="";         char ch,ch1; int l,i,j;         System.out.print("Enter Word : ");         str=in.nextLine();         l= str.length();         for(i=65;i<=90;i++) // Ascii code of Alphabetical Order         {             for(j=0;j<l;j++)             {                 ch=str.charAt(j); // Extracting word from the string                 if(ch==(char)i||ch==(char)i+32) // if extracted word is same as the given Ascii code                 {                     str1=str1+ch; // Storing string in alphabetical order                 }             }         }         System.out.println("Original Word : "+str);         System.out.println("New Word : "+str1);     } // end of main } // end of class

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Note : The program is written in the easiest way possible so try understand it. If you face any problem in understanding this program than feel free to contact/comment.

All the Best :)

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