Norm of a Number in Java
Question : Write a program to calculate Norm of a Number.
Norm of a number is square root of sum of squares of all digits of the number.
Example :-
Input : 68
6 X 6 + 8 X 8 = 100 ; Square root of 100 = 10
Output : Norm of 68 is 10.
Logic :-
First input number.
Copy the input number in another variable
extract each digit of the number
Store the sum of squares of the digit of the number in a variable say 's'
Print the square root of the result. (i.e. square root of 's')
Compile and run the program
Note : To understand the program clearly watch this video : https://youtu.be/tXDl56akraE
Program to calculate Norm of a Number :-
Checkout Source Code : Click here
Program Video : Watch Now
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