Norm of a Number

Norm of a Number in Java

Question : Write a program to calculate Norm of a Number.

Norm of a number is square root of sum of squares of all digits of the number.

Example :-

Input : 68

6 X 6 + 8 X 8 = 100 ; Square root of 100 = 10

Output : Norm of 68 is 10.

Logic :-

• First input number.

• Copy the input number in another variable

• extract each digit of the number

• Store the sum of squares of the digit of the number in a variable say 's'

• Print the square root of the result. (i.e. square root of 's')

• Compile and run the program

Note : To understand the program clearly watch this video : https://youtu.be/tXDl56akraE

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Program to calculate Norm of a Number :-

Checkout Source Code : Click here

Program Video : Watch Now